Engineering
Chemistry
Oxidation Number and Calculation
Question
Oxidation number of sulphur in marshall's acid (H2S2O8) is
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Solution
Let x be the oxidation number of sulphur in marshall's acid (H2S2O8). It contains a peroxide linkage. Thus, the oxidation number of two O atoms is −1 and that of the remaining O atoms is −2.
The oxidation number of H is +1. For the neutral molecule, the sum of the oxidation numbers is zero.
Therefore, 2(+1) + 2x + 2(−1) + 6(−2) =0 or,
x = +6 The structure is given below:
