The image shows a chemical structure with a triple bond between two carbon atoms, indicating an alkyne. The compound is propyne, CH₃C≡CH. The terminal alkyne (≡C-H) is acidic and can be deprotonated by strong bases like NaNH₂ to form the acetylide anion. This anion reacts with alkyl halides via SN2 substitution to form longer alkynes. The product P is butyne, specifically 1-butyne: HC≡C-CH₂-CH₃.

Final Answer: $HC\equiv C-{CH}_2-{CH}_3$