The given P-T graph shows two straight lines with different slopes. For an ideal gas, the ideal gas law is $PV=nRT$, which can be rearranged to $P=\left(\frac{nR}{V}\right)T$. This shows pressure is proportional to temperature at constant volume, and the slope of the P-T line is $\frac{nR}{V}$. A steeper slope indicates a smaller volume. Therefore, the process with the steeper slope (from A to B) is at constant volume V₁, and the process with the gentler slope (from B to C) is at a larger constant volume V₂.

Final Answer: The correct corresponding V-T graph is the second option, which shows a constant volume V₁ from A to B (vertical line) and a constant, larger volume V₂ from B to C (another vertical line at a higher volume).