The image shows a circuit with a battery and two resistors in parallel. The question asks for the value of Q, which is likely the charge or another electrical quantity. Since the options are images of numerical values, we need to calculate the equivalent resistance first.

For parallel resistors: $\frac{1}{R_{\mathrm{eq}}}=\frac{1}{R_1}+\frac{1}{R_2}$. With R1=3Ω and R2=6Ω, $\frac{1}{R_{\mathrm{eq}}}=\frac{1}{3}+\frac{1}{6}=\frac{1}{2}$, so Req=2Ω.

Using Ohm's Law, V=IR, the total current I = V/Req = 12V/2Ω = 6A. The current through the 6Ω resistor (I2) is found using the current divider rule: I2 = I * (R1/(R1+R2)) = 6A * (3Ω/9Ω) = 2A.

Final Answer: 2A