Engineering
Chemistry
Enthalpy of Formation Combustion and Bond
Question
Select the correct statement.
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Solution
Bond enthalpy (ΔHBE) is the energy required to break one mole of bonds in the gaseous state. For H2(g), atomization is the process of breaking H–H bonds to form H(g) atoms. Therefore, ΔHBE(H–H) equals ΔHatomisation of H2(g).
ΔHf[H(g)] is the formation enthalpy of H(g) from H2(g), which is half of ΔHatomisation since it forms 1 mole of H atoms, not 2.
Final answer: ΔHBE (H–H) is equal to ΔHatomisation of H2(g)