Show that

Engineering

Mathematics

Introduction to Determinants

Question

Show that $∣ \begin{array}{cc} \sin 10^{\circ} & - \cos 10^{\circ} \\ \sin 80^{\circ} & \cos 80^{\circ} \end{array} ∣ = 1$

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∣ \begin{array}{cc} \sin 10^{\circ} & - \cos 10^{\circ} \\ \sin 80^{\circ} & \cos 80^{\circ} \end{array} ∣

= ∣ \begin{array}{cc} \sin 10^{o} & - \cos 10^{o} \\ \cos 10^{o} & \sin 10^{o} \end{array} ∣

= sin²10º + cos²10º = 1.

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