Standard reduction potential for two electrodes are given I2 + 2e– → 2I– Eº = 0.535 V Co2+ + 2e– → Co Eº = – 0.28 V If a cell is constructed using these, then identify correct statement.

Engineering

Chemistry

EMF Calculation and Galvanic Cell

Question

Standard reduction potential for two electrodes are given
I₂ + 2e^– → 2I^– Eº = 0.535 V
Co²⁺ + 2e^– → Co Eº = – 0.28 V
If a cell is constructed using these, then identify correct statement.

Electrons will move from cobalt container to iodine container

Cathodic compartment contains iodine & iodide ion

Anion of salt bridge will move towards cobalt electrode.

All are correct

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I₂ + Co → Co⁺² + 2I¯       E° = 0.535 + 0.28
I₂ / I¯        Cathode
Co / Co²⁺    Anode
e^– move from Anode to Cathode Anion will move toward cobalt electrode.

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