Statement-1 : If equal charge is put uniformly on a surface of two identical plates one of metal and other non metal then electric field in front of metal plate will be more. Statement-2 : Electric field in front of non metal sheet is \frac{\sigma}{2 \left(\epsilon\right)_{_{0}}} where σ is the surface charge density.

Engineering

Physics

Charge and Coulombs Law

Electric Flux and Gauss Law and its Applications

Conductor

Question

Statement-1 : If equal charge is put uniformly on a surface of two identical plates one of metal and other non metal then electric field in front of metal plate will be more.
Statement-2 : Electric field in front of non metal sheet is $\frac{σ}{2 ε_{_{0}}}$ where σ is the surface charge density.

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1

Statement-1 is False, Statement-2 is True

Statement-1 is True, Statement-2 is False

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Statement-1 is false. The electric field in front of an infinite sheet of charge depends only on its surface charge density (σ), not on the material. For both a metal and a non-metal plate with the same uniform charge, the electric field magnitude is given by $\frac{σ}{2 ϵ_{0}}$ . Statement-2 is true, as this is the standard formula for the electric field due to an infinite sheet of charge.

Final Answer: Statement-1 is False, Statement-2 is True