The area of the region enclosed by the curve f(x) = max {sin⁡x, cos⁡x},

Engineering

Mathematics

Conditional Probability

Question

The area of the region enclosed by the curve f(x) = max {sin⁡x, cos⁡x}, – π ≤ x ≤ π and the x -axis is

$2 (\sqrt{2} + 1)$

$4 (\sqrt{2})$

$2 \sqrt{2} (\sqrt{2} + 1)$

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$\int_{0}^{π / 2} \sin x \cdot dx = 1$

Required area = 2 + 1 + 1 + Δ₁– Δ₂ = 4

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