Engineering
Chemistry
Electrolysis
Faraday Law
Balancing of Redox Reaction
Question
The charge required for the reduction of 1 mol of MnO4– to MnO2 is:
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Solution
Given,
MnO4– is reduced to MnO2
⇒ MnO4– + HH+ + 3C– → MnO2 + 2H2O
oxidation state of Mn in MnO4– = +7
oxidation state of Mn in MnO2 = +4
The difference in oxidation state = +3
The charge required for the reduction of 1 mol of MnO4– to MnO2 = nF
= 3F [∵ n = 3]
Answer: option-B