The coefficient of { x }^{ 4y }\quad in\quad the\quad expansion\quad of\quad (x-1)\left( x-\frac { 1 }{ 2 }  \right) \left( x-\frac { 1 }{ { 2 }^{ 2 } }  \right) ......\left( x-\frac { 1 }{ { 2 }^{ 49 } }  \right)  is equal to

Engineering

Mathematics

Application of Binomial Theorem and Summation Of Series

Summation of Series

polynomial function

Question

The coefficient of

{ x }^{ 4y }\quad in\quad the\quad expansion\quad of\quad (x-1)\left( x-\frac { 1 }{ 2 }&nbsp; \right) \left( x-\frac { 1 }{ { 2 }^{ 2 } }&nbsp; \right) ......\left( x-\frac { 1 }{ { 2 }^{ 49 } }&nbsp; \right)&nbsp;

is equal to

- 2 (1 - \frac{1}{2^{50}},)

+ve cocfficient of x.

-ve coefficient of x

- 2 (1 - \frac{1}{2^{49}},)

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