Engineering
Physics
Standing Wave on String
Question

The figure shows a simple harmonic progressive transverse wave, progressing towards the right. The particle having the maximum acceleration directed downwards is represented by

a

c

d

b

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Solution

In a transverse wave, acceleration is maximum at extreme positions and directed towards mean position. For a right-progressive wave, particles move perpendicular to propagation. The wave is moving right, so points ahead in phase lead.

Particle acceleration a=-ω2y, maximum when displacement y is maximum (amplitude). Downward acceleration means negative direction relative to positive y-axis.

Observing the wave: point d is at positive maximum displacement (crest). For a right-moving wave, the crest will next move down, so acceleration is downward (negative). Points a and c are at mean position (zero acceleration), point b is at negative maximum (acceleration upward).

Final answer: d