The following set of figures show two cases of collision between two balls. Let \left(\overset{\rightarrow}{u}\right)_{1} and \left(\overset{\rightarrow}{u}\right)_{2} be the velocities before collision and \left(\overset{\rightarrow}{V}\right)_{1} , \left(\overset{\rightarrow}{V}\right)_{2} be the velocities after collision. The coefficient of restitution, e = \frac{\left|\left(\overset{\rightarrow}{V}\right)_{2} - \left(\overset{\rightarrow}{V}\right)_{1}\right|}{\left|\left(\overset{\rightarrow}{u}\right)_{1} - \left(\overset{\rightarrow}{u}\right)_{2}\right|} Student - A : Equation holds for both cases as e is property of material of the colliding bodies. Student

Engineering

Physics

Collision

Question

The following set of figures show two cases of collision between two balls. Let ${\vec{u}}_{1}$ and ${\vec{u}}_{2}$ be the velocities before collision and ${\vec{V}}_{1}, {\vec{V}}_{2}$ be the velocities after collision. The coefficient of restitution, $e = \frac{|{\vec{V}}_{2} - {\vec{V}}_{1}|}{|{\vec{u}}_{1} - {\vec{u}}_{2}|}$

Student - A : Equation holds for both cases as e is property of material of the colliding bodies.
Student - B : Equation holds for case II only.

Both are correct

Both are incorrect

Student-A is incorrect, Student-B is correct.

Student-A is correct, Student-B is incorrect.

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

We take velocity of approach along line of collision. In first case, v_app ≠ u₁ – u₂

Please subscribe our Youtube channel to unlock this solution.