The given figure shows a ray of light as it travels from medium A to medium B. Refractive index of the medium B relative to medium A is:

Foundation

Physics Foundation

Refraction and parallel slab

Question

$\frac{\sqrt{2}}{\sqrt{3}}$

$\sqrt{2}$

$\frac{\sqrt{3}}{\sqrt{2}}$

$\frac{1}{\sqrt{2}}$

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The Snell's law simply relates angles i and r to the refraction indices of the two media A and B. Therefore, refractive index of medium B relative to

$n = \frac{\sin i}{\sin r} = \frac{\sin 60^{\circ}}{\sin 45^{\circ}} = \frac{\sqrt{3}}{\sqrt{2}}$