The locus of the foot of perpendicular drawn from the centre of the ellipse x2 + 3y2 = 6 on any tangent to it is

Engineering

Mathematics

Tangent to Ellipse

Question

The locus of the foot of perpendicular drawn from the centre of the ellipse x² + 3y² = 6 on any tangent to it is

(x² – y²)² = 6x² + 2y²

(x² + y²)² = 6x² – 2y²

(x² + y²)² = 6x² + 2y²

(x² – y²)² = 6x² – 2y²

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

T: y = mx

(k – mh)² = 6m² + 2

$where m = \frac{- h}{k}$

${(k + \frac{h^{2}}{k})}^{2} = \frac{6 h^{2}}{k^{2}} + 2$

(x² + y²)² = 6x² + 2y²