Engineering
Physics
Center of Mass
Basics of Simple Harmonic Motion
SHM of Spring Block System
Question

The mass M shown in the figure oscillates in simple harmonic motion with amplitude A. The maximum speed of junction P is V0. Assume springs are massless. Select the correct option/s

Amplitude of potential energy in springs S1 and S2 is respectively 19kA2 and kA2

V0=A8k27M

V0=A8k81M

Amplitude of potential energy in springs S1 and S2 is respectively 29 kA2 and 19 kA2

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Solution
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2k3A=kSp

Sp1=23A

Sp2=A3

U1max=12k×4A29=2kA29

U2max=122k×A29=kA29

V0=2A3×2k3m