Engineering
Chemistry
Chemical Equation and Stoichiometric Calculation
Question

The mass of P4O10 produced if 440 g of P4S3 is mixed with 384 g of O2 is

             P4S3 + O2 → P4O10 + SO2 

568 g

284 g

396 g

426 g

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Solution

               P4S3 + 8 O2 → P4O10 +  3 SO2 
gm wt.    440        384
mole    2               128
L.R.    O2    
thus 1.5 mol of P4O10 is formed
Mass of P4O10 = 1.5 × 284 = 426 g