The 'spin only' magnetic moment value of MO4–2 is_______ BM. (Where M is a metal having least metallic radii. among Sc. Ti, V, Cr, Mn and Zn).(Given atomic number : Sc = 21, Ti = 22, V = 23, Cr = 24, Mn = 25 and Zn = 30)

Engineering

Chemistry

d Block Elements and Properties

Question

The 'spin only' magnetic moment value of MO₄^–2 is_______ BM. (Where M is a metal having least metallic radii. among Sc. Ti, V, Cr, Mn and Zn).

(Given atomic number : Sc = 21, Ti = 22, V = 23, Cr = 24, Mn = 25 and Zn = 30)

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Element	Sc	Ti	V	Cr	Mn	Zn
Metallic radii (in pm)	164	147	135	129	137	137

Cr has least metallic radii
so given oxiamion is :CrO₄^–2, oxidation number of Cr = x + 4(–2) = –2; (x = +6)
So Cr⁺⁶ : 3d⁰4s⁰, No. of unpaired e– = 0
so spin only magnetic moment $μ_{m} = \sqrt{n (n + 2)}$ B.M.
μm = 0 for CrO₄^–2 ion Ans. (0)