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Question
The taxi fare in a city is as follows: For the first kilometre, the fare is Rs. 8 and for the subsequence distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y write linear equation for this information, and draw its graph.
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Solution
| x | 0 | 1 | 2 |
| y | 3 | 8 | 13 |
Given, the total distance covered = x km = 1 + (x – 1)km
Fare For first kilometre = 8
Fare for subsequent distance = 5 per km
Fare for next (x – 1) km = 5(x – 1)
Total fare = y
8 + 5(x – 1) = y
8 + 5x – 5 = y
5x – y + 3 = 0
Which is the required linear equation.
Or
y = 5x + 3
At x = 0 ,then y = 3, at x = 1, then y = 5 + 3 = 8
At x = 2, then y = 10 + 3 = 13 and so on.
Hence, this is the answer.
