Engineering
Physics
Conduction of Heat
Radiation
Question

The temperature of a body falls from 40°C to 36°C in 4 minutes when placed in a surrounding of constant temperature 20°C. Its temperature falls further from 36°C to 32°C in the same surrounding in time

(Use approximation in newton's law of cooling)

6 min

6.8 min

5.1 min

6.5 min

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Solution

Rate of fall of temperature a (θav – θ0) i.e. ΔθΔt α (θav – θ0)
where  θav  Average temp. of the body = (θin + θf )/2
θ0  Temp. of surrounding
(40364)(3632t)=[(40+362)20][(36+322)20] 
t = 5.1 min