The transfer characteristic curve of a transistor, having input and output resistance 100 Ω and 100 k Ω respectively, is shown in the figure. The Voltage and Power gain, are respectively :

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2.5 × 10⁴, 2.5 × 10⁶

5 × 10⁴, 5 × 10⁵

5 × 10⁴, 5 × 10⁶

5 × 10⁴, 2.5 × 10⁶

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$V_{gain} = (\frac{{Δℓ}_{C}}{{Δℓ}_{B}}) \frac{R_{out}}{R_{in}} = 5 \times 10^{4}$

$= \frac{1}{20} \times 10^{8} = 5 \times 10^{4}$

$P_{gain} = (\frac{{Δℓ}_{c}}{{Δℓ}_{b}}) (V_{gain})$

$= (\frac{5 \times 10^{- 3}}{100 \times 10^{- 6}}) (5 \times 10^{4})$

= 2.5 × 10⁶