The values of a for which (8,−7,a),(5,2,4) and (6,−1,2) are collinear is given by
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Ans ⇒ given, (8,–7,9), (5,2,4) & (6,–1,2) ax collinear.
Let A ≡ (8,–7,a), B ≡ (5,2,h), C ≡ (6,–1,2)
⇒ points A,B,C are collinear.
⇒ Dirction ratio of AB = AC
⇒ AB = [(5 – 8),(2 + 7),(h – a)] ⇒ [–3,9,4– a]
⇒ AC = [(6 – 8),(–1 + 7),(2 – a)] ⇒ [–2,6,2 – a])
from eqns (t),AB = AC
3(2 – a) = 2(4 – a)
6 – 3a = 8 – 2a
–3a + 2a = 8 – 6
–a = 2
∴ a = –2