Three unbiased coins are tossed, what is probability of getting exactly two heads ?

Foundation

Mathematics Foundation

Definition of Probability

Question

$\frac{1}{3}$

$\frac{3}{4}$

$\frac{2}{3}$

$\frac{3}{8}$

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Possible outcomes of tossing three coins are:
$(H H H), (H H T), (H T H), (T H H), (T T T), (T T H), (T H T), (H T T)$
here $H$ and $T$ are denoted for Head and Tail.
Total no. of outcomes $= 8$
no. of outcomes with exactly two heads $=$ $3$
$∴$ required probability = $\frac{3}{8}$
$∴$ Option D is correct.