Two glass plates are separated by water. If surface tension of water is 75 dyne/cm and the area of each plate wetted by water is 8 cm2 and the distance between the plates is 0.12 mm, then the force applied to separate the two plates is:

Engineering

Physics

Surface Tension and Surface Energy

Capillary and Pressure Difference due to Surface Tension

Question

Two glass plates are separated by water. If surface tension of water is 75 dyne/cm and the area of each plate wetted by water is 8 cm² and the distance between the plates is 0.12 mm, then the force applied to separate the two plates is:

10⁴ dyne

10⁶ dyne

10² dyne

10⁵ dyne

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$F = \frac{2 Aσ}{t} = \frac{2 \times 8 \times 75 \times 10}{012} dyne = 10^{5} dyne$