det(B) = 1
det(A) = – det(B)
det(B) = – 1
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det(B) = det(P–1AP)
det(B) = (det(P–1)) (det(A)) (det(P))
det(B) = (det(P))–1(det(A)) (det(P)) [∵ | A | | A–1 | = AA–1 | = | I | = 1]
det(B) = det(A) = 1
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