quation of  ℓ₁, ℓ₂, ℓ₃ and ℓ₄ are     y = mx + 1     ..............(1) → ℓ₁
                                                    y = mx + m    ..............(2) → ℓ₂
                                                    x + my = 0     ..............(3) → ℓ₃
                                                   my + x = 1      ..............(4) → ℓ₄
distance between  ℓ₁ and ℓ₂ = distance between  ℓ₃ and ℓ₄

$\therefore \left|\frac{\mathrm{m}-1}{\sqrt{1+{\mathrm{m}}^2}}\right|=\frac{1}{\sqrt{1+{\mathrm{m}}^2}}\Rightarrow |\mathrm{m}-1|=1\Rightarrow \mathrm{m}-1=\pm 1$

m = 2 ; m = 0 (rejected)

So, side of the square = $\frac{1}{\sqrt{5}}$

$\Rightarrow \text{ Area }=\frac{1}{5}\Rightarrow (\mathrm{p}+\mathrm{q}{)}_{\text{least }}=6$