Engineering
Physics
Center of Mass
Basics of Simple Harmonic Motion
SHM of Spring Block System
Question

Two spring block systems are shown in figure. If in both cases, the amplitude of oscillation of each of the blocks is same, then

4(Max. K.EA) = (Max. K.EB)

Max. vA > Max. vB

fA : fB = 2 : 1

TA : TB = 1

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Solution
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EB=12×2m×k2mA2

EA=12×m×km/2×A2×2=2kA2

fA=2kmfB=k2m

fAfB=2:1

vA=A=A2km

vB=B=Ak2m