Two syringes of different cross section (without needle) filled with water are connected with a tightly fitted rubber tube filled with water. Diameters of the smaller piston and larger piston are 1 cm and 3 cm respectively. If a force of 10N is applied to the smaller piston then the force exerted on the larger piston is

Engineering

Physics

BernoulIis Equation and Equation of Continuity

Question

100N

90N

30N

60N

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Since pressure is transmitted undiminished throughout the water
∴ $\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$
where F₁ and F₂ are the forces on the smaller and on the larger pistons respectively and A₁ and A₂ are the respective areas.
∴ $F_{2} = \frac{A_{2}}{A_{1}} F_{1} = \frac{π {(D_{2} / 2)}^{2}}{π {(D_{1} / 2)}^{2}} F_{1} = {(\frac{D_{2}}{D_{1}})}^{2} F_{1}$
= $\frac{{(3 \times 10^{- 2} m)}^{2}}{{(1 \times 10^{- 2} m)}^{2}} \times 10 N$ = 90N