ΔU° of combustion of methane is −X kJ mol−1. The value of ΔH° is:
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Correct option is C) Reaction;
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
Now, Δng = (np − nr) = 1 − 3 = −2
Again ΔHº = ΔUº + ΔngRT
ΔHº = − X − 2RT
∴ ΔHº < ΔU°