Foundation
Mathematics Foundation
HCF and LCM
Properties of Real Number
Linear Equations in One Variable
Question
Use Euclid's division algorithm to find the HCF of 210 and 55.
JEE Advance
College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Solution
Verified BY
Verified by Zigyan
Step 1 : Given integers are 210 and 55 such as 210 > 55 
By Euclid division lemma
210=55×3+45    ..........(i) 

Step 2 : Since remainder 45,0. So for divisor 55 and remainder 45
By Euclid division lemma
55=45×1+10   ......(ii) 
Remainder ,0 

Step 3 :  For division 45 and remainder 10 by Euclid division lemma 
45=10×4+5    ......(iii) 
Remainder 0 

Step 4 : For new divisor 10 and remainder 5 by Euclid division lemma
10=5×2+0       ........(iv) 
Hence remainder =0
So, HCF of 210,55 is 5
Question Image