Variation of equilibrium constant K with temperature T is given by van't Hoff equation : logK = logA - \frac{ΔH \circ}{2 . 303 RT} A graph between LogK and T–1 was a straight line as shown in the figure and having θ – tan–1 (– 0.5) and OP = 10. Calculate : (a) ΔH° (Standard heat of reaction) when T = 298K (b) A (pre - exponential factor) (c) Equilibrium constant K at 298K (d) K at 798K, if ΔH° is independent of temperature

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Question

Variation of equilibrium constant K with temperature T is given by van't Hoff equation :
$logK = logA - \frac{ΔH °}{2.303 RT}$
A graph between LogK and T^–1 was a straight line as shown in the figure and having θ – tan^–1 (– 0.5) and OP = 10. Calculate :
(a) ΔH° (Standard heat of reaction) when T = 298K
(b) A (pre - exponential factor)
(c) Equilibrium constant K at 298K
(d) K at 798K, if ΔH° is independent of temperature