Engineering
Physics
BernoulIis Equation and Equation of Continuity
Question
Water enters a horizontal pipe of non uniform cross section with a velocity of 0.4 ms–1 and leaves the other end with a velocity of 0.6 ms–1. pressure of water at the first end is 1500 Nm–2, then pressure at the other end is
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Solution
Bernoulli's equation for a horizontal pipe can be used to find the pressure at the second point of the pipe, which is
where
ρ is the density of the water = 1000 kg/m3
V1 is the velocity at first point = 0.6 m/s
P1 is the pressure at first point = 1500 N/m2
V2 is the velocity of second point = 0.4 m/s
P2 is the pressure at second point = ?
Putting these values in the Bernoulli's equation,
P2 = 500[(0.6)2 – (0.4)2] + 1500 = 1600 Nm–2.