Water shoots out a pipe and nozzle as shown in the figure. The cross-sectional area for the tube at point A is four times that of the nozzle. The pressure of water at point A is 41 × 103 Nm–2 (guage). If the height 'h' above the nozzle to which water jet will shoot is x/10 meter than x is. (Neglect all the losses occurred in the above process) [g = 10 m/s2].

Engineering

Physics

Question

Water shoots out a pipe and nozzle as shown in the figure. The cross-sectional area for the tube at point A is four times that of the nozzle. The pressure of water at point A is 41 × 10³ Nm^–2 (guage). If the height 'h' above the nozzle to which water jet will shoot is x/10 meter than x is. (Neglect all the losses occurred in the above process) [g = 10 m/s²].

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Cross sectional area at point 4A (tube)

Cross sectional area at point - A(nozle)

The pressure at a point A is = 41 × 10³ N/m²

= x + \frac{x}{10}

= \frac{11 x}{10}

g = 10 m/s²

P = hρg

41 \times 10^{3} = \frac{11 x}{10} \times 10 \times \frac{m}{1.1}

x = \frac{41 \times 10^{3}}{10}

The height above the nozzle x = 41 × 10² m