Foundation
Chemistry Foundation
Mole Concept and Calculation
Question

What are the products of electrolysis of one mole of pure distilled water?

4 g of H2 gas and 32 g of O2 gas are produced.

8 g of H2 gas and 8 g of O2 gas are produced.

2 g of H2 gas and 16 g of O2 gas are produced.

None of these.

JEE Advance
College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Solution

Electrolysis of water decomposes it into hydrogen and oxygen gases. The balanced chemical equation is:

2H2O2H2+O2

This shows 2 moles of water (36 g) produce 2 moles of H₂ (4 g) and 1 mole of O₂ (32 g). Therefore, 1 mole of water (18 g) would produce half these amounts: 2 g of H₂ and 16 g of O₂.

Final Answer: 2 g of H2 gas and 16 g of O2 gas are produced.