When 400 mL of 0.2 M H2SO4 solution is mixed with 600 mL of 0.1 M NaOH solution, the increase in temperature of the final solution is …………… × 10–2 K.
[Use : H+(aq) + OH– → H2O; ΔyH = –57.1 kJ mol–1
Specific heat of H2O = 4.18 J K–1 g–1
Density of H2O = 1.0 g cm–3
Assume no. change in volume of solution on mixing.]
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H2SO4 + 2NaOH Na2SO4 + 2H2O
Milimole 80 60 LR is NaOH
Or H+ + OH– H2O
Milimole 160 60 –
(160–60) 60 –
Heat released = 57.1 × 60 × 10–3 = 3.426
Total mass of solution = 1000 gram
Q = m.s.ΔT ⇒ 3426 = 1000 × 4.18 × ΔT
ΔT = 0.8196 = 81.96 × 10–2